z^2-(2i+4)z+8i=0

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Solution for z^2-(2i+4)z+8i=0 equation:


Simplifying
z2 + -1(2i + 4) * z + 8i = 0

Reorder the terms:
z2 + -1(4 + 2i) * z + 8i = 0

Reorder the terms for easier multiplication:
z2 + -1z(4 + 2i) + 8i = 0
z2 + (4 * -1z + 2i * -1z) + 8i = 0

Reorder the terms:
z2 + (-2iz + -4z) + 8i = 0
z2 + (-2iz + -4z) + 8i = 0

Reorder the terms:
8i + -2iz + -4z + z2 = 0

Solving
8i + -2iz + -4z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '4z' to each side of the equation.
8i + -2iz + -4z + 4z + z2 = 0 + 4z

Combine like terms: -4z + 4z = 0
8i + -2iz + 0 + z2 = 0 + 4z
8i + -2iz + z2 = 0 + 4z
Remove the zero:
8i + -2iz + z2 = 4z

Add '-1z2' to each side of the equation.
8i + -2iz + z2 + -1z2 = 4z + -1z2

Combine like terms: z2 + -1z2 = 0
8i + -2iz + 0 = 4z + -1z2
8i + -2iz = 4z + -1z2

Reorder the terms:
8i + -2iz + -4z + z2 = 4z + -4z + -1z2 + z2

Combine like terms: 4z + -4z = 0
8i + -2iz + -4z + z2 = 0 + -1z2 + z2
8i + -2iz + -4z + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
8i + -2iz + -4z + z2 = 0

The solution to this equation could not be determined.

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